AP ICET 26th April 2019 Shift-2

Question 136

The ratio of the sides of a triangle whose angles are in the ratio $$1 : 2 : 3$$ is

Solution

The angles will be 30,60,90

We know that, $$\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{SinC}$$

a:b:c = $$\sin A:\sin B:\sin C$$ = $$\frac{1}{2}:\frac{\sqrt{3\ }}{2}:1$$ = $$1:\sqrt{3\ }:2$$


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