A, B, C are three points on the circumference of a circle with centre O. If, in $$\triangle ABC$$. $$\angle B = 60^\circ$$ and $$\angle C = 70^\circ$$, then $$\angle BOC =$$

A

$$100^\circ$$

B

$$120^\circ$$

C

$$90^\circ$$

D

$$80^\circ$$