Question 136

The average of five numbers is 49. The average of the first and the second numbers is 48 and the average of the fourth and fifth numbers is 28. What is the third number?

Solution

Let the numbers be $$A_1 , A_2 , A_3 , A_4 , A_5$$

=> $$A_1 + A_2 + A_3 + A_4 + A_5 = 49 * 5 = 245$$

Also, $$A_1 + A_2 = 48 * 2 = 96$$

and $$A_4 + A_5 = 28 * 2 = 56$$

=> $$A_3 = 245 - 96 - 56 = 93$$


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