Question 136

How many times does the 29th day of the month occur in 400 consecutive years?

In every year, 29th date appears 11 times i.e. in every month except February.
This will amount to 11*400 = 4400 times.
However, in every leap year, 29th date appears 1 moreΒ time in February.
So, the number of leap years:
Years divisible by 4: 400 / 4 = 100
Subtract non-leap century years (divisible by 100 but not 400): -3 (e.g., 100, 200, 300)
Total leap years = 100 - 3 = 97 occurrences.
So, total occurrences = 4400 + 97 = 4497.

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