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$$y = x \sin x \Rightarrow \frac{dy}{dx} =$$
$$x \cos x + \sin x$$
$$x \cos x - \sin x$$
$$\cos x + x \sin x$$
$$x \sin x - \cos x$$
Given, $$y = x \sin x$$
$$\Rightarrow$$ $$\frac{dy}{dx}=x\cdot\left(\frac{d}{dx}\sin\ x\right)+\sin\ x\cdot\left(\frac{d}{dx}x\right)=x\cdot\cos\ x+\sin\ x$$
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