Question 135

$$x = \sqrt{x + y} \Rightarrow \frac{dy}{dx} =$$

Solution
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Given, $$x=\sqrt{\ x+y}$$

$$\Rightarrow$$  $$x^2=\ x+y$$

$$\Rightarrow$$  $$y=x^2-x$$

$$\Rightarrow$$  $$\frac{dy}{dx}=2x-1$$

Hence, the correct answer is Option D

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