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$$x = \sqrt{x + y} \Rightarrow \frac{dy}{dx} =$$
1 - x
1 + x
1 - 2x
2x - 1
Given, $$x=\sqrt{\ x+y}$$
$$\Rightarrow$$ย $$x^2=\ x+y$$
$$\Rightarrow$$ ย $$y=x^2-x$$
$$\Rightarrow$$ ย $$\frac{dy}{dx}=2x-1$$
Hence, the correct answer is Option D
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