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The derivative of $$f(x) = \frac{x^{3}+3}{x-1}$$
$$\frac{(x-1)x-(x^{2} +3)}{(x-1)^{2}}$$
$$\frac{(x-1)2x-(x^{2} +3)}{(x-1)^{2}}$$
$$\frac{(x+1)x-(x^{2} +3)}{(x-1)^{2}}$$
$$\frac{(x-1)2x-(x^{2} -3)}{(x-1)^{2}}$$
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