Question 135

In ΔABC, DE || AC. D and E are two points on AB and CB respectively. If AB = 10 cm and AD = 4 cm, then BE : CE is

Solution


AB = 10 and AD = 4

=> BD = 10-4 = 6

Since, DE | | AC

=> $$\frac{AB}{BD} = \frac{BC}{BE}$$

=> $$\frac{10}{6} = \frac{BE + EC}{BE}$$

=> $$5BE = 3BE + 3EC$$

=> $$\frac{BE}{CE}$$ = 3 : 2


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