Question 135
In ΔABC, DE || AC. D and E are two points on AB and CB respectively. If AB = 10 cm and AD = 4 cm, then BE : CE is
Solution
AB = 10 and AD = 4
=> BD = 10-4 = 6
Since, DE | | AC
=> $$\frac{AB}{BD} = \frac{BC}{BE}$$
=> $$\frac{10}{6} = \frac{BE + EC}{BE}$$
=> $$5BE = 3BE + 3EC$$
=> $$\frac{BE}{CE}$$ = 3 : 2
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