If $$y = \frac{7x^2 + 3x}{x^3 + 5}$$, then $$\left(\frac{dy}{dx}\right)_{x=2} =$$

A

$$\frac{5}{39}$$

B

$$\frac{-5}{39}$$

C

$$\frac{-5}{169}$$

D

$$\frac{5}{169}$$