Question 135

If $$\frac{a}{b}+\frac{b}{a}=2$$, then the value of a-b is:

Solution

Given : $$\frac{a}{b}+\frac{b}{a}=2$$

=> $$\frac{a^2+b^2}{ab}=2$$

=> $$a^2+b^2=2ab$$

=> $$a^2+b^2-2ab=0$$

=> $$(a-b)^2=0$$

=> $$a-b=0$$

=> Ans - (C)


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