Solution
Given : $$\frac{a}{b}+\frac{b}{a}=2$$
=> $$\frac{a^2+b^2}{ab}=2$$
=> $$a^2+b^2=2ab$$
=> $$a^2+b^2-2ab=0$$
=> $$(a-b)^2=0$$
=> $$a-b=0$$
=> Ans - (C)
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