ABC is a right angled triangle. B being the right angle. Midpoints of AB,BC and AC are respectively B’,C' and A’. Area of ΔA’B’C’ is

A

$$\frac{1}{2}$$ x area of AABC

B

$$\frac{2}{3}$$ x area of AABC

C

$$\frac{1}{4}$$ x area of AABC

D

$$\frac{1}{8}$$ x area of AABC