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$$\log_{5}{25} + \log_{2} (\log_{3}{81})$$ is
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$$\log\left(a^m\right)\ =\ m\log\left(a\right)\ and\ \ \log_aa$$ = 1
$$\log_55^2\ +\ \log_2\left(\log_33^4\right)$$
2 +Â $$\ \log_24$$
2+Â $$\ \log_22^2$$
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