Question 134

A shopkeeper marks his goods 20% higher than the cost price and allows a discount of 5%. The percentage of his profit is.

Solution

Let cost price = Rs. $$100$$

Markup % = 20%

=> Marked price = $$100+(\frac{20}{100}\times100)$$

= $$100+20=Rs.$$ $$120$$

After allowing discount of 5%, => Selling price = $$120-(\frac{5}{100}\times120)$$

= $$120-6=Rs.$$ $$114$$

$$\therefore$$ Profit % = $$\frac{(114-100)}{100}\times100=14\%$$

=> Ans - (A)

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