Question 133

Two cubes have their volumes in the ratio 27 : 64. The ratio of their surface areas is

Solution

let the side of 1st cube and 2nd cube be a unit and b unit respectively

now volume of a cube = $$side^3$$

total surface area of cube = 6$$side^2$$

given that : $$\frac{a^3}{b^3} = \frac{27}{64}$$

$$\frac{a}{b} = \frac{3}{4}$$

Now we can say that

$$\frac{6a^2}{6b^2} = \frac{9}{16}$$

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