Question 133

If the length of a diagonal of a square is $$6\sqrt{2}$$ cm, then its area will be

Solution

Let side of the square = $$s$$ cm and length of diagonal = $$6\sqrt{2}$$ cm

=> $$(s)^2+(s)^2=(6\sqrt2)^2$$

=> $$2s^2=72$$

=> $$s^2=\frac{72}{2}=36$$ -------------(i)

$$\therefore$$ Area of square = $$s^2=36$$ $$cm^2$$

=> Ans - (D)

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