Question 132

Pipe A and B can empty a full tank in 18 hours and 24 hours,respectively.Pipe C alone can fill the tank in 36 hours.If the tank is $$\frac{5}{6}$$ full and all the three pipes

Solution

As per the given question,

A can fill the tank in=18 hours

B can fill the tank in=24 hours

C can empty the tank in 36 hours

If all the three are opened, then the tank will fill in 1 hour$$=\dfrac{1}{18}+\dfrac{1}{24}-\dfrac{1}{36}=\dfrac{4+3-2}{72}=\dfrac{5}{72}$$

The tank will be filled in$$=\dfrac{72}{5}$$

Hence $$\dfrac{5}{6}$$ will be filled in $$=\dfrac{5}{6}\times\dfrac{72}{5}=12hours.$$

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