Question 132
Pipe A and B can empty a full tank in 18 hours and 24 hours,respectively.Pipe C alone can fill the tank in 36 hours.If the tank is $$\frac{5}{6}$$ full and all the three pipes
Solution
As per the given question,
A can fill the tank in=18 hours
B can fill the tank in=24 hours
C can empty the tank in 36 hours
If all the three are opened, then the tank will fill in 1 hour$$=\dfrac{1}{18}+\dfrac{1}{24}-\dfrac{1}{36}=\dfrac{4+3-2}{72}=\dfrac{5}{72}$$
The tank will be filled in$$=\dfrac{72}{5}$$
Hence $$\dfrac{5}{6}$$ will be filled in $$=\dfrac{5}{6}\times\dfrac{72}{5}=12hours.$$
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