Question 132

If A is 48% more than B and C is 60%less than the sum of A and B, then A is what percentage more than C? (Correct to one decimalplace.)

Solution

Let B = 100 $$x$$

Here A =$$ 148 x$$

C = 60% less than A+B

= $$\dfrac{40}{100} \times 248x $$

$$\Rightarrow \dfrac{992}{100} x $$

$$\Rightarrow 99.2x $$

Now A is more than C = $$148x - 99.2x $$

$$\Rightarrow 48.8x$$

% more than C = $$\dfrac{48.2x}{99.2x}\times 100$$

$$\Rightarrow 49.19 $$ %

$$\Rightarrow 49.2$$ % Ans

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: