If $$x^{2} -7x + 1 = 0$$, then what is the value of $$x + \frac{1}{x}$$?
Given : $$x^2-7x+1=0$$
Dividing both sides by $$'x'$$
=> $$x-7+\frac{1}{x}=0$$
=> $$x+\frac{1}{x}=7$$
=> Ans - (A)
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