Question 130

Two positive whole numbers are such that the sum of the first and twice the second number is 8 and their difference is 2. The numbers are:

Solution

Let the numbers be $$x$$ and $$(x-2)$$

According to ques,

=> $$x+2(x-2)=8$$

=> $$x+2x-4=8$$

=> $$3x=8+4=12$$

=> $$x=\frac{12}{3}=4$$

$$\therefore$$ Numbers are = 4, 2

=> Ans - (D)


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