The two parallel sides of a trapezium are 27 cm and 13 cm respectively. If the height of the trapezium is 8 cm, then what is its area in m$$^2$$?
Area of trapezium = $$\frac{1}{2}\times$$ (sum of parallel sides) $$\times h$$
= $$\frac{1}{2}\times(27+13)\times8 $$
= $$4\times40=160$$ $$cm^2$$
= $$0.016$$ $$m^2$$
=> Ans - (A)
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