A merchant has 1000 kg sugar, part of which he sells at 8% profit and the rest at 18% profit. He gains 14% on the whole. The quantity sold 8% profit is:
Let quantity sold at 8% profit = $$x$$ kg
=> Quantity sold at 18% profit = $$(1000-x)$$ kg
According to ques,
=> $$8(x)+18(1000-x)=14(1000)$$
=> $$8x+18000-18x=14000$$
=> $$10x=18000-14000=4000$$
=> $$x=\frac{4000}{10}=400$$
$$\therefore$$ The quantity sold 8% profit = $$400$$ kg
=> Ans - (C)
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