Peter starts from a point A in a playground and walks $$100\ \text{m}$$ towards East. Then he walks 30 m towards North and then 70 m towards West and then finally 10 m North to reach the point B. The distance between A and B (in metres) is
Solution
Walking 100 m East and later 70 m West leaves him $$100 - 70 = 30$$ m East of A. Walking 30 m North and later 10 m North leaves him $$30 + 10 = 40$$ m North of A. So AB is the longest side of a right angled triangle with the other two sides 30 m and 40 m, giving $$AB = \sqrt{30^2 + 40^2} = \sqrt{2500} = 50$$ m.
Get AI Help
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
