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If the sum of the diagonals of a rhombus is L and the perimeter is 4P, find the area of the rhombus?
$$\frac{1}{4}(L^2 - P^2)$$
$$\frac{1}{4}(L^2 - 4P^2)$$
$$\frac{1}{2}(L^2 - 4P^2)$$
$$\frac{1}{4}(L^2 + 3P^2)$$
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