Let the five consecutive even integers in ascending order be x, x+2, x+4, x+6, x+8
$$\Rightarrow$$ x + x + 2 + x + 4 + x + 6 + x + 8 = S
$$\Rightarrow$$ 5x + 20 = S
$$\Rightarrow$$ x = $$\frac{S-20}{5}$$
$$\therefore\ $$Least number among them = x = $$\frac{S-20}{5}$$
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