Question 128
Three circles of radii 3.5 cm, 4.5 cm and 5.5 cm touch each other externally. Then the perimeter of the triangle formed by joining the centres of the circles, in cm, is
Solution
=> AD = AE = 3.5 cm
and BD = DF = 4.5 cm
and CF = CE = 5.5 cm
Perimeter of $$\triangle$$ ABC = AD+AE+BD+BF+CF+CE
= 2 * (3.5 + 4.5 + 5.5)
= 2 * 13.5 = 27 cm
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