Solution
It is given that 2 sin θ cos θ = 1
we know that (sinθ)^2 + (cos θ ) ^2 = 1
so , 2 sin θ cos θ = (sin θ)^2 + (cos θ )^2........(1)
Dividing the whole equation 1 by sin θ cos θ, we get
2 = (sinθ)/(cosθ) + (cosθ)/(sinθ)
tan θ + cot θ = 2
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