If x, y(x < y) are primes satisfying x + y = 30, then the number of such pairs (x, y) is
we have given
x + y = 30, and x, y(x < y)
then we have
y - x > 0
y > x
then y should be positive integer and the x have the following condition
x > 0
x = 0
x < 0
so we have three pair of satisfying the condition of (x,y) in equation x + y = 30 answer
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