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if (2, 0) is a solution of the linear equation 2x+3y=K, then the value of K is
5
2
6
4
Given (2,0) is a solution of the equation 2x + 3y = k.
Substitute x = 2 and y = 0Â
k = 2(2) + 3(0) = 4
Hence, option D is the correct answer.
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