In an election between two candidates, 80% of the voters cast their votes, out of which 5% votes were declared invalid. A candidate got 9500 votes which were 80% of the valid votes. Find the total number of voters enrolled in that election.

Let the total number of voters enrolled in the election be $$N$$.

1. 80% of the voters actually cast their votes.
Hence, total votes cast $$= 0.80\,N$$.

2. Of the votes cast, 5% were declared invalid.
Valid votes $$= (1 - 0.05)\times 0.80\,N = 0.95 \times 0.80\,N = 0.76\,N$$.

3. One candidate secured 9500 votes, which were 80% of the valid votes.
Therefore, $$0.80 \times (0.76\,N) = 9500$$.
Simplifying gives $$0.608\,N = 9500$$.

4. Solve for $$N$$:
$$N = \frac{9500}{0.608} = 15625$$.

Hence, the total number of voters enrolled in the election is 15625.

Option C which is: 15625