Question 125

Find the value of $$\frac{4+3\sqrt{3}}{7+4\sqrt{3}}$$ is

Solution

Expression : $$\frac{4+3\sqrt{3}}{7+4\sqrt{3}}$$

= $$\frac{4+3\sqrt{3}}{7+4\sqrt{3}} \times \frac{7 - 4\sqrt{3}}{7 - 4\sqrt{3}}$$

= $$\frac{28 - 16\sqrt{3} + 21\sqrt{3} - 36}{49-48}$$

= $$5\sqrt{3} - 8$$

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