Solution
Expression : $$\frac{4+3\sqrt{3}}{7+4\sqrt{3}}$$
= $$\frac{4+3\sqrt{3}}{7+4\sqrt{3}} \times \frac{7 - 4\sqrt{3}}{7 - 4\sqrt{3}}$$
= $$\frac{28 - 16\sqrt{3} + 21\sqrt{3} - 36}{49-48}$$
= $$5\sqrt{3} - 8$$
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
