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The remainder when $$f(x) = 4x^{3} - 3x + 9$$ is divided by $$3x - 2$$ is
$$f\left(-\frac{3}{2}\right)$$
$$f\left(\frac{3}{2}\right)$$
$$f\left(\frac{2}{3}\right)$$
$$f\left(-\frac{2}{3}\right)$$
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