$$\frac{17}{30}+\left[3\frac{1}{5}-\left\{\frac{5}{6}-\left(3\frac{4}{5}\div 9\frac{1}{2}\right)\right\}\right]$$ is equal to: 

A

$$\frac{1}{5}$$

B

$$\frac{10}{3}$$

C

$$\frac{3}{5}$$

D

$$\frac{11}{3}$$