A city X has six villages around it. The population of village A is 25% of the population of city X while that of village B is 20% of that of city X. The population of village C is 2/5th of that of city X. The population of village D is 60% of that of village ‘C. The population of village E is 85% of that of village B. The population of village F is 21000 which is 35% of that of city X.
By what per cent is the population of village E less than that of village A ?
Let the populations of villages X,A,B,C,D,E,F be x,a,b,c,d,e,f respectively
Given that
a = 0.25x
b=0.2x
c=0.4x
d=0.6*0.4x=0.24x
e=0.85*0.2x=0.17x
f=0.35x=21000
Hece x = 60000
per cent by which the population of village Eis less than that of village A
= $$(0.25x-0.17x)/0.25x \times 100$$
=$$0.08/0.25 \times 100 $$
=32
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