Question 124

$$5a + \frac{1}{3a}$$ = 5, the value of 9a2 + $$\frac{1}{25a^2}$$ is 

$$5a + \frac{1}{3a}$$ = 5
Multiplying both the sides by (3/5)
$$3a + \frac{1}{5a}$$ = 3
Now squaring both sides
9a2 + $$\frac{1}{25a^2}$$ - 6/5 = 9
Hence 9a2 + $$\frac{1}{25a^2}$$ = 39/5

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