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The table given below shows the runs scored by 5 players in four matches.
Question 123
Runs scored by C in match II is how much percent more than the runs scored by C in match I?
Solution
Runs scored by C in match I = 60
Runs scored by C in match II = 68
=> Required % = $$\frac{(68-60)}{60}\times100$$
= $$\frac{800}{60}=13.33\%$$
=> Ans - (D)
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