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In a circle centred at O, PQ is a tangent at P. Furthermore, AB is the chord of the circle and is extended to Q. If PQ = 12 cm and QB = 8 cm, then the length of AB is equal to:
Using the tangent-secant theorem: $$PQ^2=QB \times QA$$
$$\Rightarrow$$ $$12^2=8\times (8+AB)$$
$$\Rightarrow$$ $$18=8+AB$$
$$\Rightarrow$$ $$AB=10$$ cm.
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