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Question 122
In triangle ABC, ∠BAC = 75°, ∠ABC = 45°. BC is produced to D. If ∠ACD = x°, then X/3 % of 60° is
Solution
Using exterior angle property, we get :
=> $$\angle$$ACD = $$\angle$$ABC + $$\angle$$BAC
=> x = 45° + 75° = 120°
Now, $$\frac{x}{3}$$% of 60°
= $$\frac{120}{3}$$% of 60° = $$\frac{40}{100} * 60$$
= 24°
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