Question 122

If the expression $$15^{6} \times 28^5 \times 55^7$$ is evaluated, the number of zeros at the end of the number is

Solution

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Expression : $$15^{6} \times 28^5 \times 55^7$$

Number of 2's in the expression (in $$28^5$$) = $$(2)^{10}=10$$

Number of 5's = $$(5)^6\times(5)^7=13$$

$$\because$$ number of 2's are less than number of 5's, thus number of zeroes will depend on two, hence number of zeroes are 10

=> Ans - (B)

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