Question 122

ABC is an isosceles triangle such that AB = AC and ∠B = 35°. AD is the median to the base BC. Then ∠BAD is:

Solution

In an isosceles triangle, a median is also perpendicular to the base.

Now, in $$\triangle$$ABD

=> $$\angle$$ABD + $$\angle$$ADB + $$\angle$$BAD = 180°

=> 35° + 90° + $$\angle$$BAD = 180°

=> $$\angle$$BAD = 180° - 125° = 55°

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