Two boys A and B are opposite side of a tower of height 150mts. They measure the angle of elevation of top of the tower as $$30^{\circ}$$ and $$60^{\circ}$$. Then the distance between the boys (in mts)

A

$$\frac{600}{\sqrt{3}}$$

B

$$\frac{550}{\sqrt{3}}$$

C

$$\frac{650}{\sqrt{3}}$$

D

$$\frac{450}{\sqrt{3}}$$