If the numerator of a fraction is increased by 40% and the denominator is doubled the new fraction obtained is $$\frac{7}{16}$$ . What was the original fraction ?
Let the original fraction be $$\frac{p}{q}$$
The numerator when increased by 40% becomes = 1.4p
The denominator when doubled becomes = 2q
Hence, $$\frac{1.4p}{2q} = \frac{7}{16}$$
$$\frac{p}{q} = \frac{10}{16} = \frac{5}{8}$$
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