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A man walking away from the foot of a cliff 150 meters high observes that it take 2 minutes to change the angle of elevation of the top of the cliff from $$60^{\circ}$$ to $$45^{\circ}$$. His walking speed in kmph is
$$\frac{9+3\sqrt{3}}{2}$$
$$\frac{9-3\sqrt{3}}{2}$$
$$\frac{3(1+3\sqrt{3})}{2}$$
$$\frac{3(\sqrt{3}-1)}{2}$$
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