Solution
$$\cot(1950^{\circ})=\cot\left(5\left(360^{\circ\ }\right)+150^{\circ\ }\right)$$
$$=\cot150^{\circ\ }$$
$$=\cot\left(180^{\circ}-30^{\circ\ }\right)$$
$$=-\cot30^{\circ\ }$$
$$=-\sqrt{3}$$
Hence, the correct answer is Option B
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