Question 120

The value of $$\cot (1950^\circ)$$ is

Solution

$$\cot(1950^{\circ})=\cot\left(5\left(360^{\circ\ }\right)+150^{\circ\ }\right)$$

$$=\cot150^{\circ\ }$$

$$=\cot\left(180^{\circ}-30^{\circ\ }\right)$$

$$=-\cot30^{\circ\ }$$

$$=-\sqrt{3}$$

Hence, the correct answer is Option B

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