Question 12

What is the value of $$\surd121 + \surd12321 + \surd1234321 + \surd123454321$$?

Solution

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We know that 
11^2 =121
111^2 = 12321
1111^2 =1234321
11111^2=123454321
Now therefore taking root of RHS and adding we get
11+111+1111+11111 = 12344

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