In $$\triangle$$ ABC, O is the orthocentre and $$\angle$$ BOC = $$80^\circ$$, the measure of $$\angle$$ BAC is
Given : $$\angle$$ BOC = $$80^\circ$$
To find : $$\angle$$ BAC = ?
Solution : In case of orthocentre, we have :
$$\angle$$ BOC + $$\angle$$ BAC = $$180^\circ$$
=> $$80^\circ+\angle$$ BAC = $$180^\circ$$
=> $$\angle$$ BAC =Â $$180-80=100^\circ$$
=> Ans - (C)
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