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The sum of three numbers is 243. If the ratio of the first to the second is 2:3 and that of the second to the third is 3:4, then the second number is
LET THE THREE NUMBERS IN THE ORDER BE A,B AND C.
GIVEN :
A+B+C = 243Β Β Β Β Β (1)
A/B = 2/3, SO 3A = 2B
AND B/C = 3/4, SO 4B = 3C
PUTTING VALUES OF B IN EQUATION 1, WE GETΒ
B = 81, A = 54 AND C= 108
SECOND NUMBER IS 81.
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