In $$\triangle$$ ABC, $$\angle C = 90^\circ$$. M and N are the mid-points of sides AB and AC,respectively. CM and BN intersect each other at D and $$\angle BDC = 90^\circ$$. If BC = 8 cm, then the length of BN is:

A

$$6\sqrt{3}$$ cm

B

$$6\sqrt{6}$$ cm

C

$$4\sqrt{6}$$ cm

D

$$8\sqrt{3}$$ cm