Study the given information carefully and answer the question that follow:
A basket contains 4 red 5 blue and 3 green marbles.
If the three marbles are picked at random what is the probability that at least one is blue ?
Required probability = 1 - Prob. that no ball is blue = $$1- \frac{^7C_3}{^{12}C_3} = 37/44$$
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