SSC CGL 2012 Tier 1

Question 118

If the distance between two point (0, -5) and (x, 0) is 13 unit, then x =

Solution

$$Distance^{2} = diff.of x cordinates^{2}+diff.of y coordinates^{2}$$
$$13^{2}=x^{2}+5^{2}$$
Hence $$x=\pm12$$

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